For an atom with atomic numner `14` the number of orbits and orbitals in which elrctrons are prresent are respectively :

Options

A. ` 3,6`
B. ` 6,3`
C. ` 7,3`
D. 3,8

Explanation

To determine the number of orbits and orbitals for an atom with atomic number 14, we can follow these steps:

### Step 1: Identify the Element
The atomic number 14 corresponds to the element Silicon (Si).

### Step 2: Write the Electronic Configuration
To find the electronic configuration, we distribute the 14 electrons in the available energy levels (or shells):
- The first shell can hold a maximum of 2 electrons (1s²).
- The second shell can hold a maximum of 8 electrons (2s² 2p⁶).
- The third shell can hold a maximum of 18 electrons, but since we only have 4 electrons left after filling the first two shells, we fill it as follows: (3s² 3p²).

So, the complete electronic configuration for Silicon (atomic number 14) is:
1s² 2s² 2p⁶ 3s² 3p².

### Step 3: Count the Number of Orbits
The number of orbits (or shells) is determined by the highest principal quantum number (n) in the electronic configuration:
- The first shell (n=1) has 2 electrons.
- The second shell (n=2) has 8 electrons.
- The third shell (n=3) has 4 electrons.

Since the highest principal quantum number is 3, there are **3 orbits**.

### Step 4: Count the Number of Orbitals
Next, we need to count the number of orbitals in each shell:
- The first shell (n=1) has 1s orbital (1 orbital).
- The second shell (n=2) has 2s and 2p orbitals (1 + 3 = 4 orbitals).
- The third shell (n=3) has 3s and 3p orbitals (1 + 3 = 4 orbitals).

Now, we sum the orbitals:
- Total orbitals = 1 (from n=1) + 4 (from n=2) + 4 (from n=3) = **9 orbitals**.

### Final Answer
Thus, for an atom with atomic number 14, the number of orbits is **3** and the number of orbitals is **9**.

### Summary
- Number of orbits: 3
- Number of orbitals: 9