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If the series limit of wavelngth of the ...

If the series limit of wavelngth of the Lymman series for the hydrogen atoms si ` 912Å` , then the serice limit of wavelngth for the Balmer seies fo the hydrogen atom si :

A

` 912Å`

B

`912 xx 2 Å`

C

`912 xx 4Å`

D

`912 //2Å`

Text Solution

Verified by Experts

The correct Answer is:
C
`(1)/(lambda_(Lyman)) =R_(H) [ 1/1^2 - 1/(prop^2)]`,
`(1)/(lambda_("Balmer")) =R_(H) [ (1)/1^(2) -(1)/(prop^(2))]`.
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Knowledge Check

  • If the series limit of wavelength of the Lyman series for the hydrogen atoms is 912 Å, then the series limit of wavelength for the Balmer series of the hydrogen atom is:

    A
    912 Å
    B
    `912 xx 2` Å
    C
    `912xx4` Å
    D
    `912//2` Å

  • If the series limit of wavelength of the Lyman series for the hydrogen atoms is 912 Å, then the series limit of wavelength for the Balmer series of the hydrogen atom is:

    A
    912 Å
    B
    `912 xx 2` Å
    C
    `912xx4` Å
    D
    `912//2` Å

  • The series limit wavelength of the Balmer series for the hydrogen atom is

    A
    `1/R`
    B
    `4/R`
    C
    `9/R`
    D
    `16/R`

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