If the series limit of wavelngth of the Lymman series for the hydrogen atoms si ` 912Å` , then the serice limit of wavelngth for the Balmer seies fo the hydrogen atom si :

Options

A. ` 912Å`
B. `912 xx 2 Å`
C. `912 xx 4Å`
D. `912 //2Å`

Answer

C

Explanation

`(1)/(lambda_(Lyman)) =R_(H) [ 1/1^2 - 1/(prop^2)]`,
`(1)/(lambda_("Balmer")) =R_(H) [ (1)/1^(2) -(1)/(prop^(2))]`.