The shortest wavelength in H sopecitrum of lyman series when `R_(H) = 109678 cm^(-1)` is

Options

A. ` 911 Å `
B. `700Å `
C. `600Å`
D. `811Å `

Answer

A

Explanation

For shortest ` lambda` of Lyman series .
` n_(1) = 1` and `n_(2) = prop , (1)/(lambda) = R_(H) [1/n_(1)^(2) - (1)/(n_(2)^(2))]`
because ` Delta E = (hc)/( lambda) ` is maxumum when `lambda` is small ,
thus `Delta E = E_(prop) - E_(1)`.