A boll of mass `200 g` is moving with a velocity of ` 10 m sec^(-1)` . If the error in measurement of velocity is ` 0. 1%`, the uncertainty in its position is :

Options

A. ` 3. 3 xx 10^(31) m`
B. ` 3.3 xx 10^(-27) m`
C. ` 5.3 xx 10^(-25) m`
D. ` 2.64 xx 10^(-32)m`

Answer

D

Explanation

`Delta u = ( 0.1)/(100 ) xx 10 =10^(-2) m sec ^(-7)`
Now ` Delta u. Delta x = h/(4 pim)`
` therefore Delta x = (6.625 xx 10^(-34))/(4 xx 10^(-2) xx 3. 14 xx 200 xx 10^(-3))`
` = 2. 46 xx 10^(-32) m`.