` psi_(310)` has :

Options

A. `1` aredial node and `1` angualr node
B. `1` aredial node and `1` angualr node
C. `1` aredial node and `1` angualr node
D. `1` aredial node and `1` angualr node

Explanation

To solve the question regarding the wave function \( \psi_{310} \), we need to analyze the quantum numbers associated with it and determine the number of angular nodes and areal (spherical) nodes present in the orbital.

### Step-by-Step Solution:

1. **Identify the Quantum Numbers**:
The notation \( \psi_{310} \) indicates the following quantum numbers:
- \( n = 3 \) (Principal quantum number)
- \( l = 1 \) (Azimuthal quantum number)
- \( m = 0 \) (Magnetic quantum number)

2. **Calculate Total Nodes**:
The total number of nodes in an orbital can be calculated using the formula:
\[ \text{Total nodes} = n - 1 \]
For \( n = 3 \):
\[ \text{Total nodes} = 3 - 1 = 2 \]

3. **Determine Angular Nodes**:
The number of angular nodes is equal to the azimuthal quantum number \( l \):
\[ \text{Angular nodes} = l = 1 \]

4. **Calculate Areal (Spherical) Nodes**:
The number of areal nodes can be found by subtracting the number of angular nodes from the total nodes:
\[ \text{Areal nodes} = \text{Total nodes} - \text{Angular nodes} = 2 - 1 = 1 \]

5. **Conclusion**:
Therefore, for the wave function \( \psi_{310} \):
- Angular nodes = 1
- Areal nodes = 1

### Final Answer:
- **Angular Nodes**: 1
- **Areal Nodes**: 1