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The differnce between nth and (n+1) the ...

The differnce between nth and `(n+1)` the Bohr radius of B atom is equal to be its `(n-1)` th Bohr radius .The value of n is

A

`1`

B

`2`

C

`3`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
D
`r_n =r_1 xxn^2 , r__(n+1) = r_1 xx (n+1)^2`
` r_(n-1) = r_n (n-1)^2`
`:. R_(n+1) =r_n = r_1 [n^2 + 2 n+ 1 -n^2]`
` =r_1 (2 n+1)`
` r_( n-1) = r _(n+1)^(-r_n)` ltbRgt ` :. (n-1)^2 = 2n +1`
` :. N=4`.
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