When an electron fo mass `6` m and charge `6e` moves with a velocity of `7u` about the nuclar charge `Ze` in a circular orbit fo radius ` r` . The potential energy of the electron will be:

Options

A. ` Zw`
B. ` (Ze^2)/r`
C. `(- 6Ze^2)/r`
D. `(2 pi^2 me^4 Z^2)/( n^2h^2)`

Answer

C

Explanation

`P.E. = int_(prop)^r ( 6 Ze^2)/r^2 dr`
` = 6 Zw^2 [-1/e]^r`
` =- (6 ZE^2)/r`.