If ` lambda_0` is the Threshold wavelength of a metal for photoelencron emisssion . If the metal is exposed to the light of wavelngth ` lambda` then the velocity of ejectred electgron will be ` sqrt ((2h)/m ( lambda_0 - lambda) K )`. The value fo (K) is :

Options

A. `1`
B. `c/( lambda_0 lambda)`
C. `1/( lambda lambda_0)`
D. `(c. lambda)/( lambda_0)`

Answer

B

Explanation

` (hc)/(lambda) = (hc)/(lambda_0) + 1/2 mv^2`
` v= sqrt ( (2hc)/(m)) [(lambda_0 -lambda)/(lambdalambda_0)]`
`:. K = c/(lambda lambda_0)`.