The number fo electrons present in ` 1 cm^3 ` of ` Mg` (density of `. _(12)Mg^(24) g cm^(-3))` is:

Options

A. `5 . 24 xx 10^(23)`
B. ` 4 lambda//3`
C. `3 lambda`
D. `3 lambda//4`

Answer

A

Explanation

`w_(Mg) 1 cm^3 = 1. 74 g`
` :.` No . Of elecrron `= ( 1. 74 xx 12 xx 6.023 xx 10^(23))/(24)`
` = 5.24 . xx 10^(23)`.