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A metal surface having v0 as threshode ...

A metal surface having ` v_0` as threshode frequency is incident by light of frequency (v) then select the correct :

A

` u = sqrt(2 h(lambda_0 - lambda))`

B

` u = sqrt(2 h(lambda_0 - lambda))`

C

` u = sqrt(2 h(lambda_0 - lambda)/(m))`

D

` u = sqrt (2 h(lambda_0 - lambda)/(m))`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
`hv = hv_0 + 1/2 mu^2`
` :. U = sqrt(2h (v-v_0)/m)0 = sqrt((2hc (lambda_0 - lambda)/(mx lambda_0 xx lambda))`
` hv = w + 1/2 mu^2`
` :. U = sqrt((2 (hv-w))/m)`.
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