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The wavelength of the radiation emitted ...

The wavelength of the radiation emitted , when in a hydrogen atom electron falls from infinity to stationary state 1 , would be :
(Rydberg constant = `1.097 xx 10^(7) m^(-1)`)

A

` 9. 1 xx 10^(-8) nm`

B

` 192 nm`

C

`406 nm`

D

` 91 nm`

Text Solution

Verified by Experts

The correct Answer is:
D

` 1/( lambda ) =R_H [1/( oo)- 1/1^2]`
` :. lambda = 1/(R_H) = 1/(1. 097 xx 10^7)` ltbRgt ` = 9. 1 xx 10 ^(-8)m`
` = 91 xx 10^(-9) m = 91 nm`.
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