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The sping only maagentic mome ( in Bohr ...

The sping only maagentic mome ( in Bohr magneton , `M_C)` of ` Hi^(2+)` in aqueouse solution would be :

A

` 2. 84`

B

`4 . 90`

C

`0`

D

`1.73`

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The correct Answer is:
A

`Ni^(2+) : 1s^2 , 2s^2 2p^t6 , 3s^2 3p^6 3d^8`
(with two unpairel dlectrons )
The manganetic moment
` = sqrt ( n (n + 2)) = sqrt ( 2(2+2)) = sqrt 8= 2.83 BM`.
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The spin-only magnetic moment [in units of Bohr magneton, (mu_(B) of Ni^(2+) in aqueous solution would be (atomic number of Ni=28)

The "spin-only" magnetic moment [in units of Bohr magneton, (mu_B) ] or Ni^(2+) in aquenous solution would be : (At no. Ni = 28 ).

Assertion (A): The "spin only” magnetic moment [in units of Bohr magneton, ( mu_(B) )] of Ni^(2+) in aqueous solution would be (atomic number Ni= 28) 2.84 BM Reason (R): The metal ion has 2 unpaired electrons

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