The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of excited state(s) for the electron in the Bohr orbit of hydrogen is(are)

Options

A. ` - 3 . 4 eV`
B. ` - 4 . 3 eV`
C. ` - 6. 8 eV`
D. ` + 6 . 8 eV`

Answer

A

Explanation

` E_n =E_1/n^2 = (-13.6)/2^2 =- 3 . 4eV`.