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Find out the numer fo angualr nodes in t...

Find out the numer fo angualr nodes in the orbital to which the last electron of Cr enter .

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The correct Answer is:
2
`Cr = [Ar] 3d^5 , 4s^1`
the last electron of Cr enres the 3d-subshell
` :.` No . Of angualr nodes , l =2 .
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