Magnetic moment fo ` A^(2+)` ion is ` 5.48 xx 10^(-23) J//R`. Find out the number of unpaired elecrrons in it . `(9. 27 xx 10^(-24) J//T = 1B . M.)` .

Answer

5

Explanation

Magnetic momnt `= 5 . 48 xx 10^(-23) J/T`
` = (5 48. xx 10^(-23))/(9 9. 27 xx 10^(24)) = 5. 92 B.m.`
`:. sqrt(n(n+2)) = 5. 92 = sqrt(35)`
` :. N=5`
` :.` No. fo unjparied electrons ` =5` .