A single electron system has ionization enrgy ` 1. 118 xx 10^7 J mol^(-1)`. Calculate the numner of protons in the nucleus fo te system .

Answer

3

Explanation

`:.` Ionization enrgy ` = Z^2 /n^2 xx 21. 69. xx 10^(-19) J`
` :. ( 1.118 xx 10^7)/( 6.023 xx 10^(23)) = (Z^2)/((1)^2) xx 2 1. 69 xx 10^(-19)`
` :. Z=3`.