A photon of ` 300 nm` is abosorbed by a gas and then re-emits two photons . One re-emitted photon has wavelength ` 496nm` . Caluclate energy of other photon re-emitteed out .

Explanation

To solve the problem step by step, we will use the principles of energy conservation and the relationship between energy and wavelength of photons.

### Step 1: Understand the given data
We have the following information:
- Wavelength of the absorbed photon, \( \lambda_0 = 300 \, \text{nm} \)
- Wavelength of one re-emitted photon, \( \lambda_1 = 496 \, \text{nm} \)

We need to find the wavelength of the other re-emitted photon, \( \lambda_2 \), and its energy.
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