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For the reaction at 298 K: A((g))+B((g...

For the reaction at `298 K`:
`A_((g))+B_((g))hArrD_((g))+C_((g))`
`DeltaH^(@)=29.8 kcal` and `DeltaS^(@)=100calK^(-1)`. Calculate the value of equilibrium constant.

Text Solution

Verified by Experts

`DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)`
`=29.8xx10^(3)-298xx100=0`
`:' DeltaG^(@)=-2.303RT log K_(c)`
`:. 0=-2.303RT log K_(c)`
or `K_(c)=1.0`
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