When `S` in the form of `S_(8)` is heated at `900 K`, the initial pressure of `1 atm` falls by `29%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the `K_(p)` for reaction.

Explanation

`{:(,S_(8(g)),hArr,4S_(2(g))),("Initial mole",1,,0),("Pressure of equilibrium",(1-0.29),,(4xx0.29)),(,=0.71,,=1.16):}`
`:' `Pressure of `S_(8)` reduces by `0.29 atm` ltbrlt Now `K_(p)=([P'_(S_(2))]^(4))/([P'_(S_(8))])=([1.16]^(4))/(0.71)=2.55(atm)^(3)`