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Consider the reaction A(g)+B(g) hArr C...

Consider the reaction
`A(g)+B(g) hArr C(g)+D(g)`
Which occurs in one step. The specific rate constant are `0.25` and `5000` for the forward and reverse reaction, respectively. The equilibrium constant is

A

`2.0xx10^(-4)`

B

`4.0xx10^(2)`

C

`5.0xx10^(-5)`

D

`2.5xx10^(-6)`

Text Solution

Verified by Experts

`K_(f)=0.25`, `K_(b)=5000`
`:' K_(c)=(K_(f))/(K_(p))=(0.25)/(5000)=5.0xx10^(-5)`
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