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At equilibrium K(p)=1, then :...

At equilibrium `K_(p)=1`, then :

A

`DeltaG^(@)=0`

B

`DeltaG^(@)=+ve`

C

`DeltaG^(@)=-ve`

D

none of these

Text Solution

Verified by Experts

`DeltaG^(@)= -2.303 RT log K_(p)`
If `K_(p)=1`, `DeltaG^(@)=0`
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