Amount of `PCl_(5)` (in moles) need to be added to one litre vessel at `250^(@)C` in order to obtain a concentration of `0.1 "mole"` of `Cl_(2)` for the given change is:
`PCl_(5)hArrPCl_(3)+Cl_(2)` , `K_(c)=0.0414 mol litre^(-1)`

Options

A. `0.3415`
B. `0.0341`
C. `3.415`
D. `0.3145`

Explanation

`{:(,PCl_(5),hArr,PCl_(3),+,Cl_(2)),("Initial moles",a,,0,,0),("Mole at equilibrium",(a-0.1),,0.1,,0.1):}`
`K_(c)=((0.1)/(1)xx(0.1)/(1))/((a-0.1)/(1))` (`:' Volume is 1 litre`)
or `0.0414=(0.01)/((a-0.1))`
`:. A=0.3415 "mole"`