For `NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g)`, the observed, pressure for reaction mixture in equilibrium is `1.12` atm at `106^(@)C`. What is the value of `K_(p)` for the reaction?

Options

A. `3.316 atm^(2)`
B. `0.3136 atm^(2)`
C. `31.36 atm^(2)`
D. `6.98 atm^(2)`

Explanation

`{:(,NH_(4)HS_((s)),hArr,NH_(3(g)),+,H_(2)S_((g))),("Pressure at equilibrium",,,P,,P):}`
`:. ` Total pressure at equilibrium `=2P=1.12 atm`
`:. P=1.12//2atm`
`:' K_(p)=P'_(NH_(3))xxP'_(H_(2)S)`
`:. K_(p)(1.12)/(2)xx(1.12)/(2)=0.3136 atm^(2)`