Home
Class 11
CHEMISTRY
Densities of diamond and graphite are 3....

Densities of diamond and graphite are `3.5` and `2.3 g mL^(-1)`, respectively. The increase of pressure on the equilibrium `C_("diamond") hArr C_("graphite")`

A

favours backward reaction

B

favours forward reaction

C

have no effect

D

nothing can be predicted

Text Solution

Verified by Experts

Le Chatelier principle is not valid for solid-solid systems.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Integer|12 Videos
  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Comprehension|22 Videos
  • CHEMICAL BONDING

    P BAHADUR|Exercise Exercise 7|11 Videos
  • GASEOUS STATE

    P BAHADUR|Exercise Exercise -9|1 Videos

Similar Questions

Explore conceptually related problems

The enthalpies of combustion of diamond and graphite are - 395.4 kJ and - 393.5 kJ respectively calculate the enthalpy of transformation from diamond to graphite.

" Hybridized states of carbon in graphite and diamond are respectively "

Densities of diamond and graphite are (3.5g)/(mL) and (2.3g)/(mL) . Delta_(r)H=-1.9(kJ)/("mole") Favourable conditions for formation of diamond are:

At 5xx10^(4) bar pressure density of diamond and graphite are 3 g//c c and 2g//c c respectively, at certain temperature 'T' .Find the value of DeltaU-DeltaH for the conversion of 1 mole of graphite to 1 mole of diamond at temperature 'T' :

At 500 kbar pressure density of diamond and graphite are 3 "g"//"cc" and 2 "g"//"cc" respectively, at certain temperature T. Find the value of |DeltaH-DeltaU| ("in kJ"//"mole") for the conversion of 1 mole of graphite 1 mole of diamond at 500 kbar pressure. (Given : 1 "bar" = 10^(5) "N"//"m"^(2))

The enthalpies of combustion of C_(("graphite")) and C_(("diamond")) are -393.5 and -395.4kJ//mol respectively. The enthalpy of conversion of C_(("graphite")) to C_(("diamond")) in kJ/mol is:

P BAHADUR-CHEMICAL EQUILIBRIUM-Exercise
  1. Densities of diamond and graphite are 3.5 and 2.3 g mL^(-1), respectiv...

    Text Solution

    |

  2. Write equilibrium constant for the each : (a) N(2)O(4(g))hArr2NO(2(g...

    Text Solution

    |

  3. The equilibrium constant expression for a gas reaction is : K(c) = (...

    Text Solution

    |

  4. The equilibrium constant of the reaction , SO(3(g))hArrSO(2(g))+(1)/...

    Text Solution

    |

  5. Calculate the equilibrium constant for the reaction, H(2(g))+CO(2(g)...

    Text Solution

    |

  6. For the reactions, N(2(g))+3H(2(g))hArr2NH(3(g)). At 400 K, K(p)=41 at...

    Text Solution

    |

  7. Find out the value of K(c) for each of the following equilibrium from ...

    Text Solution

    |

  8. The rate of reversible reaction (change in concentration per second): ...

    Text Solution

    |

  9. Write a stoichiometric equation for the reaction between A(2) and C wh...

    Text Solution

    |

  10. In which case does the reaction go farthest to completion: K=1 K, K=10...

    Text Solution

    |

  11. The equilibrium constant K(c) for A((g))hArrB((g)) is 1.1. Which gas h...

    Text Solution

    |

  12. Calculate the value of equilibrium constant K(p) for the reaction: O...

    Text Solution

    |

  13. Equilibrium constant, K(c) for the reaction, N(2(g))+3H(2(g))hArr2NH...

    Text Solution

    |

  14. The ester , ethyl acetate is formed by the reaction of ethanol and ace...

    Text Solution

    |

  15. Consider the following equations for cell reaction: A+BhArrC+D ….(1)...

    Text Solution

    |

  16. For the gasesous reaction, 2NO(2)hArrN(2)O(4), calculate DeltaG^(@) an...

    Text Solution

    |

  17. DeltaG^(@) for (1)/(2)N(2)+(3)/(2)H(2)hArrNH(3) is -16.5 kJ mol^(-1) a...

    Text Solution

    |

  18. Calculate the values of DeltaE^(@) and DeltaH^(@) for the reaction: ...

    Text Solution

    |

  19. For the reaction at 298 K: A((g))+B((g))hArrD((g))+C((g)) DeltaH^(...

    Text Solution

    |

  20. Calculate the value of equilibrium constant for the reaction: A((g))...

    Text Solution

    |

  21. Calculate the pressure for CO(2) at equilibrium if DeltaG^(@)=31.1kcal...

    Text Solution

    |