For the reactions,
`{:(AhArrB, K_(c)=2), (BhArrC, K_(c)=4), (ChArrD, K_(c)=6):}`
`K_(c)` for the reaction, `AhArrD` is:

Options

A. `(2+4+6)`
B. `(2xx4)//6`
C. `(4xx6)//2`
D. `2xx4xx6`

Explanation

To find the equilibrium constant \( K_c \) for the reaction \( A \rightleftharpoons D \) using the given reactions and their equilibrium constants, we can follow these steps:

### Step 1: Write the given reactions and their equilibrium constants.

1. \( A \rightleftharpoons B \) with \( K_{c1} = 2 \)
2. \( B \rightleftharpoons C \) with \( K_{c2} = 4 \)
3. \( C \rightleftharpoons D \) with \( K_{c3} = 6 \)

...