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2 "mole" N(2) and 3 "mole" H(2) gas are ...

`2 "mole" N_(2)` and `3 "mole" H_(2)` gas are allowed to react in a `20 L` flask at `400 K` and after complete conversion of `H_(2)` into `NH_(3)`. `10 L H_(2)O` was added and temperature reduced to `300 K`. Pressure of the gas after reaction is :
`N_(2)+3H_(2)to2NH_(3)`

A

`3Rxx300//20`

B

`3Rxx300//10`

C

`Rxx300//20`

D

`Rxx300//10`

Text Solution

Verified by Experts

`underset(1)underset(2)(N_(2))+underset(0)underset(3)(3H_(2))tounderset(2)underset(0)(2NH_(3))`,
`NH_(3)` is dissolved in water. The remaining gas is `1 "mole" ` of `N_(2)` having pressure.
`P=(n)/(V)RT=(1)/(10)xxRxx300=30R`
Note that `10litre H_(2)O` occupies `10 litre` volume of container.
`:. V_(vessel)` left available far gas
`=20-10=10 litre`
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P BAHADUR-CHEMICAL EQUILIBRIUM-Exercise
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  16. For the gasesous reaction, 2NO(2)hArrN(2)O(4), calculate DeltaG^(@) an...

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  19. For the reaction at 298 K: A((g))+B((g))hArrD((g))+C((g)) DeltaH^(...

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