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The degree of dissociation of PCl(5) (al...

The degree of dissociation of `PCl_(5) (alpha)` obeying the equilibrium, `PCl_(5)hArrPCl_(3)+Cl_(2)` is related to the pressure at equilibrium by :

A

`a prop P`

B

`a prop (1)/(sqrt(P))`

C

`a prop (1)/(P^(2))`

D

`a prop (1)/(P^(4))`

Text Solution

AI Generated Solution

To find the relationship between the degree of dissociation (α) of \( PCl_5 \) and the pressure at equilibrium, we can follow these steps: ### Step 1: Write the equilibrium reaction The equilibrium reaction for the dissociation of \( PCl_5 \) is: \[ PCl_5 \rightleftharpoons PCl_3 + Cl_2 \] ...
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P BAHADUR-CHEMICAL EQUILIBRIUM-Exercise
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  5. Calculate the equilibrium constant for the reaction, H(2(g))+CO(2(g)...

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  6. For the reactions, N(2(g))+3H(2(g))hArr2NH(3(g)). At 400 K, K(p)=41 at...

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  13. Equilibrium constant, K(c) for the reaction, N(2(g))+3H(2(g))hArr2NH...

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  15. Consider the following equations for cell reaction: A+BhArrC+D ….(1)...

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  16. For the gasesous reaction, 2NO(2)hArrN(2)O(4), calculate DeltaG^(@) an...

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  17. DeltaG^(@) for (1)/(2)N(2)+(3)/(2)H(2)hArrNH(3) is -16.5 kJ mol^(-1) a...

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  18. Calculate the values of DeltaE^(@) and DeltaH^(@) for the reaction: ...

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  19. For the reaction at 298 K: A((g))+B((g))hArrD((g))+C((g)) DeltaH^(...

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