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The equilibrium : PCl(5(g))hArrPCl(3(g))...

The equilibrium : `PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))` shows that `K_(p) (atm)` is double to the value of `K_(c)` (`mol litre^(-1)`) at a particular temperature `T`, then `T` is :

A

`2 K`

B

`12.18 K`

C

`24.36 K`

D

`27.3 K`

Text Solution

Verified by Experts

`(K_(p))/(K_(c))=(RT)^(Deltan)`,
`:. 2=(0.0821xxT)^(1)`
`:. T=24.36 K`
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P BAHADUR-CHEMICAL EQUILIBRIUM-Exercise
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  7. Find out the value of K(c) for each of the following equilibrium from ...

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  10. In which case does the reaction go farthest to completion: K=1 K, K=10...

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  13. Equilibrium constant, K(c) for the reaction, N(2(g))+3H(2(g))hArr2NH...

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  15. Consider the following equations for cell reaction: A+BhArrC+D ….(1)...

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  16. For the gasesous reaction, 2NO(2)hArrN(2)O(4), calculate DeltaG^(@) an...

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  17. DeltaG^(@) for (1)/(2)N(2)+(3)/(2)H(2)hArrNH(3) is -16.5 kJ mol^(-1) a...

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  18. Calculate the values of DeltaE^(@) and DeltaH^(@) for the reaction: ...

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  19. For the reaction at 298 K: A((g))+B((g))hArrD((g))+C((g)) DeltaH^(...

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