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The graph relates. In K(eq.) vs.(1)/(T) ...

The graph relates. In `K_(eq.) vs.(1)/(T)` for a reaction. The reaction must be:

A

exothermic

B

endothermic

C

`DeltaH` is negligible

D

high spontaneous at ordinary temperature

Text Solution

Verified by Experts

In `(K_(2))/(K_(1))=(DeltaH)/(R )[(T_(2)-T_(1))/(T_(1)T_(2))]`
Since `K` increase with decrease of temperature and thus `DeltaH=-ve`.
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P BAHADUR-CHEMICAL EQUILIBRIUM-Exercise
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