The equilibrium constant for the given reaction:
`SO_(3(g))hArrSO_(2(g))+1//2O_(2(g))`, `(K_(c)=4.9xx10^(-2))`
The value of `K_(c)` for the reaction:
`2SO_(2(g))+O_(2(g))hArr2SO_(3(g))`, will be :

Options

A. `416`
B. `2.40xx10^(-3)`
C. `9.8xx10^(-2)`
D. `4.9xx10^(-2)`

Explanation

`K_(c_(1))=([SO_(2)][O_(2)]^(1//2))/([SO_(3)])=4.9xx10^(-2)`
`K_(c_(2))=([SO_(3)]^(2))/([SO_(2)]^(2)[O_(2)])=[(1)/(K_(c_(1)))]^(2)=[(1)/(4.9xx10^(-2))]^(2)`
`=416.5`