The equilibrium constant `K_(p_(1))` and `K_(p_(2))` for the reactions `XhArr2Y` and `ZhArrP+Q`, respectively are in the ratio of `1:9`. If the degree of dissociation of `X` and `Z` be equal, then the ratio of total pressure at these equilibrium is:

Options

A. `1:36`
B. `1:1`
C. `1:3`
D. `1:9`

Explanation

`underset((1-x))underset(1)(X)hArrunderset(2x)underset(0)(2Y)`
`K_(p_(1))=((2x)^(2))/((1-x))((P_(1))/(1+x))^(1)`
`underset((1-x))underset(1)(Z)hArrunderset(x)underset(0)(P)+underset(x)underset(0)(Q)`
`K_(p_(2))=(x^(2))/((1-x))((P_(2))/(1+x))^(1)`
`(4xxP_(1))/(P_(2))=(1)/(9)`
`:. (P_(1))/(P_(2))=(1)/(36)`