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If Ag^(+)+NH(3)hArr[Ag(NH(3))]^(+), K(1)...

If `Ag^(+)+NH_(3)hArr[Ag(NH_(3))]^(+)`, `K_(1)=3.5xx10^(-3)` and `[Ag(NH_(3))]^(+)+NH_(3)hArr[Ag(NH_(3))_(2)]^(+)`, `K_(2)=1.74xx10^(-3)`. The formation constant of `[Ag(NH_(3))_(2)]^(+)` is :

A

`6.08xx10^(-6)`

B

`6.8xx10^(-6)`

C

`1.6xx10^(3)`

D

`1.088xx10^(7)`

Text Solution

Verified by Experts

`K_(1)=([Ag(NH_(3))]^(+))/([Ag^(+)][NH_(3)])=3.5xx10^(-3)`...(`i`)
`K_(2)=([Ag(NH_(3))_(2)]^(+))/([Ag(NH_(3))]^(+)[NH_(3)])=1.74xx10^(-3)`....(`ii`)
`K_(3)=K_(1)xxK_(2)=([Ag(NH_(3))_(2)]^(+))/([Ag^(+)][NH_(3)]^(2))` ....(`iii`)
`K_(3)` for `Ag^(+)+2NH_(3)to[Ag(NH_(3))_(2)]^(+)`
By eqs. (`i`), (`ii`) and (`iii`),
`K_(3)=K_(1)xxK_(2)`
`=3.5xx10^(-3)xx1.74xx10^(-3)`
`=6.08xx10^(-6)`
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Ag^(+)+NHP(3)hArr[Ag(NH_(3))]^(+), K_(1)=3.5=10^(-3) [Ag(NH)_(3)]^(+)+NH_(3)hArr[Ag(NH_(3))_(2)]^(+),K_(2)=1.7xx10^(-3) then the formation constant of [Ag(NH_(3))_(2)]^(+) is

Ag^(+)+hArr|Ag(NH_(3))_(2)|^(+), k_(1) = 6.8 xx 10^(-3) [Ag(NH_(3))]^(+) + NH_(3)hArr |Ag(NH_(3))_(2)|, k_(2) = 1.6xx10^(-3) Then the formation constant or |Ag(NH_(3))_(2)|^(+) is

Ag^(+) + NH_(3) ltimplies [Ag(NH_(3))]^(+), k_(1)=6.8 xx 10^(-5) [Ag(NH_(3))]^(+) + NH_(3) ltimplies [Ag(NH_(3))_(2)]^(+) , k_(2) = 1.6xx10^(-3) The formation constant of [Ag(NH_(3))_(2)]^(+) is :

{:(Ag^+ +NH_3 hArr[Ag(NH_3)]^+,,K_1=3.5xx10^-3),([Ag(NH_3)]^+ +NH_3 hArr[Ag(NH_3)_2]^+,,K_2=1.8xx10^-3):} then, the overall formation constant of [Ag(NH_3)_2]^+ is :

Zn^(+2) + 2NH_(3) hArr [Zn(NH_(3))_(2)]^(+2), K_(1) = 2xx10^(-3) [Zn(NH_(3))_(2)]^(+2) + 2NH_(3) hArr [Zn(NH_(3))_(4)]^(2+), K_(2) = 1.5xx10^(-3) Find out the instability constant?

The hybridisation of Ag in [Ag(NH_3)_2]^(+) complex is

P BAHADUR-CHEMICAL EQUILIBRIUM-Exercise
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