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In the reaction, PCl(5)hArrPCl(3)+Cl(2),...

In the reaction, `PCl_(5)hArrPCl_(3)+Cl_(2)`, the amounts of `PCl_(5)`, `PCl_(3)` and `Cl_(2)`, `2 moles` each at equilibrium and the total pressure is `3 atm`. Find the equilibrium constant `K_(p)`.

Text Solution

Verified by Experts

`K_(p)=(n_(Cl_(2))xxn_(PCl_(3)))/(n_(PCl_(3)))xx[(P)/(sumn)]^(1)`
`=(2xx2)/(2)xx[(3)/(6)]^(1)=1.0 atm`
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