Home
Class 11
CHEMISTRY
For the equilibrium, N(2)O(4)hArr2NO(2) ...

For the equilibrium, `N_(2)O_(4)hArr2NO_(2)` , `(G_(N_(2)O_(4))^(@))_(298)=100kJ//mol` and `(G_(NO_(2))^(@))_(298)=50kJ//mol`.
(`a`) When `5 mol/litre` of each is taken, calculate the value of `DeltaG` for the reaction at `298 K`.
(`b`) Find the direction of reaction.

Text Solution

Verified by Experts

`{:(,N_(2)O_(4),hArr,2NO_(2)),("Conc. at t=0",5,,5):}`
`:' DeltaG^(@)` for the reaction `=2xxG_(NO_(2))^(@)-G_(N_(2)O_(4))^(@)`
`=2xx50-100=0`
Now, `DeltaG=DeltaG^(@)+2.303RTlog_(10)Q`
`=0+2.303xx8.314xx10^(-3)xx298xxlog"(5^(2))/(5)`
`=+3.99 kJ~~4kJ`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Comprehension|22 Videos

  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Statement:Explanation|13 Videos

  • CHEMICAL EQUILIBRIUM

    P BAHADUR|Exercise Exercise|134 Videos

  • CHEMICAL BONDING

    P BAHADUR|Exercise Exercise 7|11 Videos

  • GASEOUS STATE

    P BAHADUR|Exercise Exercise -9|1 Videos

Similar Questions

Explore conceptually related problems

For the equilibrium at 298 K, N_(2)O_(4)(g) hArr 2NO_(2)(g), G_(N_(2)O_(4))^(ɵ)=100 kJ mol^(-1) and G_(NO_(2))^(ɵ)=50 kJ mol^(-1) . If 5 mol of N_(2)O_(4) and 2 moles of NO_(2) are taken initially in one litre container than which statement are correct.

For an equilibrium reaction, N_(2)O_(4)(g) hArr 2NO_(2)(g) , the concentrations of N_(2)O_(4) and NO_(2) at equilibrium are 4.8 xx 10^(-2) and 1.2 xx 10^(-2) mol//L respectively. The value of K_(c) for the reaction is

For the reaction equilibrium, N_(2)O_(4(g))hArr2NO_(2(g)) , the concentration of N_(2)O_(4) and NO_(2) at equilibrium are 4.8xx10^(-2) and 1.2xx10^(-2) mol/L respectively. The value of K_(c) for the reaction is:

For the equilibrium reaction 2NO_2(g) hArr N_2O_4(g) + 60.0 kJ the increase in temperature

In the reaction equilibrium N_(2)O_(4) hArr 2NO_(2)(g) When 5 mol of each is taken and the temperature is kept at 298 K , the total pressure was found to be 20 bar. Given : Delta_(f)G_(n_(2)O_(4))^(ɵ)=100 kJ, Delta_(f)G_(NO_(2))^(ɵ)=50 KJ a. Find DeltaG of the reaction at 298 K . b. Find the direction of the reaction.

Calculate DeltaG^@ for the reaction NO hArr 1/2N_2(g) +1/2O_2(g) If K=1.55xx10^15 at 298 K

For the reaction, SO_(2)(g)+1//2O_(2)(g)hArrSO_(3)(g) DeltaH_(298)^(@)=-98.32KJ//mol e,DeltaS_(298)^(@)=-95.0J//mol e-K . Find the K_(p) for this reaction at 298K.