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In a reaction at equilibrium, 'x' mole o...

In a reaction at equilibrium, `'x'` mole of reactant `A` decompose to give `1 molar` of `C` and `D`. It has been found that the fraction of `A` decomposed at equilibrium is independent of initial concentration of `A`. Find the value of `x`.

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`{:(,xA,hArr,C,+,D),("Before diss.",a,,0,,0),("At equilibrium",a(1-alpha),,aalpha//x,,aalpha//x):}`
Where `alpha` is degree of dissociation of `A`.
`:. K_(c)=([C][D])/([A]^(x))=(a^(2)alpha^(2)xxV^(x))/(a^(x)(1-alpha)^(x)xxV^(2)xx x^(2))`
(`:' V` is total volume. )
`=(a^(2-x)xxV^(x-2)xxalpha^(2))/((1-alpha)^(x)xx x^(2))`
Since `alpha` is independent of `a`, then
`:. 2-x=0` or `x=2`
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