A graph plotted between `log_(10) K_(c)` and `1//T` is straight line with intercept `10` and slpoe equal t0 `0.5.` Calculate :
(`i`) pre -exponential factor `A`.
(`ii`) heat of reaction at `298 K`.
(`iii`) equilibrium constant at `298 K`.
(`iv`) equilibrium constant in at `800 k` assuming `DeltaH` remains constant in between `298 K` and `800 K`.

Explanation

(`i`) `10^(10)`, (`ii`) `-2.303 cal mol^(-1)`, (`iii`) `1.004xx10^(10)`, (`iv`) `1.001xx10^(10)`