`H_(2)` and `I_(2)` are mixed at `400^(@)C` in a `1.0 L` container, and when equilibrium is established, the following concentrations are present: `[HI]=0.8 M, [H_(2)]=0.08 M`, and `[I_(2)]=0.08 M`. If now an additional `0.4` mol of HI is added, what are the new equilibrium concentrations, when the new equilibrium `H_(2)(g)+I_(2)(g) hArr 2HI(g)` is re-established?

Explanation

`[H_(2)]=0.1516 M`, `[I_(2)]=0.1316 M`, `[HI]=0.5468 M` ,