Calculate `K_(c )` for the reaction `KI + I_(2) hArr KI_(3)`. Given that initial weight of `KI` is `1.326 g` weight of `KI_(3)` is `0.105 g` and number of moles of free `I_(2)` is `0.0025` at equilibrium the volume of solution is `1-L`.

Explanation

`0.032` ,