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Ca(3)(PO(4))(2) is insoluble in in water...

`Ca_(3)(PO_(4))_(2)` is insoluble in in water. On adding a few drops of HCI to solid `Ca_(3)(PO_(4))_(2)` in contant with water, the solid dissolves. The reason is:

A

the solvent becomes more polar on adding HCI

B

`Ca_(3)(PO_(4))_(2)` combines with HCI to form soluble `CaCI_(2)`

C

`Ca(H_(2)PO_(4))_(2)` is formed, which dissolves

D

`H_(3)PO_(4)`, a weak acid is formed and the solubility product of `Ca_(3)(PO_(4))_(2)` decrease

Text Solution

Verified by Experts

The correct Answer is:
B
`Ca_(3)(PO_(4))_(2)+6HCIrarr underset("soluble")(3CaCI_(2))+2H_(3)PO_(4)`
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