When HCI gas is passed through a saturated solution of common salt, pure NaCI is Precipitated because:

Options

A. the impurities dissolve in HCI
B. HCI is highly soluble in `H_(2)O`
C. the product of `[Na^(+)]` and `[CI^(-)]` exceeds the solubiluity product of NaCI
D. the solulbility product of NaCI is lowest by the chloride in form aqueous HCI

Answer

C

Explanation

`NaCI_((s))hArr Na_((aq.))^(+)+CI_((aq.))^(-), HCIrarr H^(+)+CI^(-)` The increase in `[CI^(-)]` brings in an increases in `[Na^(+)][CI^(-)]`, which will lead for backward reaction because `K_(SP_(NaCI))= [Na^(+)][CI^(-)]`