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Calculate K for the reaction, A^(-)+H(3)...

Calculate K for the reaction, `A^(-)+H_(3)^(+)O hArr HA+H_(2)O`
if `K_(a)` value for the acid HA is `1.0xx10^(-6)`.

A

`1xx10^(-6)`

B

`1xx10^(12)`

C

`1xx10^(-12)`

D

`1xx10^(6)`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(a)=10^(-6)for HA+H_(2)OhArrH_(3)O^(+)A^(-)`
Thus K for reverse reaction is
`(1)/(10^(-6))=10^(6)`
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