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pH of a mixture containing 0.10 M X^(-) ...

`pH` of a mixture containing `0.10 M X^(-)` and `0.20 M HX` is: `[pK_(b)(X^(-))=4]`

A

`4+log2`0

B

`4-log 2`

C

`10+log2`

D

`10-log2`

Text Solution

Verified by Experts

The correct Answer is:
D

`pOH= pK_(b)+log ([sal t])/([Base])= 4+ log (0.2)/(0.1)`
`:. pOH= 4+log 2and pH=10-log 2`
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