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Zn salt is mixed with (NH(4))(2)S of mol...

Zn salt is mixed with `(NH_(4))_(2)S` of molarity `0.021M`. The amount of `Zn^(2+)` reamins unprecipitated in 12 mL of this solutikon : `(K_(SP)for ZnS=4.51xx10^(-24))`

A

`1.677xx10^(-22)g`

B

`1.767xx10^(-22)g`

C

`2.01xx10^(-23)g`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`[NH_(4))_(2)S]=0.021M`
`:. [S^(2-)]=0.021M`
`:' "At equilibrium", [Zn^(2+)][S^(2-)]=K_(SP)of ZnS`
`:. [Zn^(2+)]= (4.51xx10^(-24))/(0.021)= 2.15xx10^(-22)M`
`[Zn^(2+)]` left in solution
`= 2.15xx10^(-22)xx65g//litre`
`= (2.15xx10^(-22)xx65xx12)/(1000)g//12mL`
`= 1.677xx10^(-22)g//12mL`
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