A certain buffer solution contains equal contration of `X^(-)` and `HX`. The `K_(b)` for `X^(-)` is `10^(-10)`. The pH of the buffer is:

Answer

4

Explanation

Given, `[X^(-)]=[HX]`
`:' K_(b)for X^(-)=10^(-10)`
`:. K_(b) for HX=10^(-4)` , `(:' K_(a)xxK_(b)=10^(-14))`
`:. pH= -log K_(a)+ log ([Sal t])/([Acid])`
`:. pH= -log 10^(-4)` or `pH =4`