Calculate the pH of `0.01M` solution of `AICI_(3), (K_(a)` of `[AI(H_(2)O)_(6)]^(3+)` is `1.4xx10^(-5))`

Answer

3

Explanation

`AICI_(3)+6H_(2)Orarr[AI(H_(2)O)_(6)]^(3+)+3CI^(-)`
`:' [H^(+)]= sqrt(K_(a)xxc)=sqrt(1.4xx10^(-5)xx0.10)`
`=1.183xx10^(-3)`
Now, `pH= - log[H^(+)]= -log 1.183xx10^(-3)`
`=3-log1.183`
`implies pH =2.927~~3`