Home
Class 11
CHEMISTRY
For the given reaction, RNH(2)+H(2)OhA...

For the given reaction,
`RNH_(2)+H_(2)OhArr RNH_(3)^(+)+OH^(-)`. Find the pOH value for `10^(-2)N RNH_(2)` solution.

Text Solution

Verified by Experts

The correct Answer is:
3
`RNH_(2)+H_(2)Oharr RNH_(3)^(+)+OH^(-)`
`[OH^(-)]=c.alpha=sqrt((K_(b))/(c )).c=sqrt(K_(b).c)`
`=sqrt((K_(w))/(K_(a)).c)=sqrt((10^(-14))/(10^(-10))xx10^(-2))`
`=sqrt(10^(-6))=10^(-3)`
`:. pOH=3`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise7|33 Videos

  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise|85 Videos

  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise4|32 Videos

  • GASEOUS STATE

    P BAHADUR|Exercise Exercise -9|1 Videos

  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise 9 Advanced numerical problems|61 Videos

Similar Questions

Explore conceptually related problems

Complete the following reaction: RNH_(2)+H_(2)SO_(4)to

In the reaction NO_(2)^(-) +H_(2)O rarr NO_(3)^(-)+2H^(+)+"n"e^(-) What is the value of "n" ?

For the reaction N_(2) (g) + 3 H_(2) (g) hArr 2 NH_(3) (g) " at " 400 K , K_(p) = 41 Find the value of K_(p) for the following reaction : 1/2 N_(2) (g) + 3/2 H_(2) hArr NH_(3) (g)

The equilibrium constant for the ionization of RNH_(2) (g) in water as RNH_(2)(g)+H_(2)O(l)hArrRNH_(3)^(+)(aq)+OH^(-)(aq) is 8xx10^(-6) at 25^(@)C. find the pH of a solution at equilibrium when pressure of RNH_(2) (g) is 0.5 bar :

The hydrolysis constant for the reaction, H_(2)PO_(4)^(-)+H_(2)hArrH_(3)PO_(4)+OH^(-) is 1.4xx10^(-12) . The ionisation constant for H_(3)PO_(4)+H_(2)OhArr H_(2)PO_(4)^(-)+H_(3)O^(+) is:

The reaction RNH_(2) + CHCI_(3) + 3KOH to RNC + 3KCl + 3H_(2)O is know as

For the following equilibrium NH_(3)+H_(2)O hArr NH_(4)^(+)+OH^(-) calculate the equilibrium constant, if for the equilibrium, NH_(4)^(+)+H_(2)OhArr NH_(4)OH+H^(+) the equilibrium constant is 5.5xx10^(-10)

As the base changes from RNH_(2) to R_(2)NH_(1) to R_(3)N the basicity

P BAHADUR-IONIC EQUILIBRIUM-Exercise6
  1. K(a) for HCN is 5.0xx10^(-10) at 25^(@)C. For maintaining a constant p...

    Text Solution

    |

  2. A solution containing 75 mL of 0.2M HCI and 25 mL of 0.2M NaOH. Calcul...

    Text Solution

    |

  3. Calculate the change in pH of water when 0.01 mole of NaOH are added i...

    Text Solution

    |

  4. Calculate the pH at which an acid indicator with K(a) = 1.0 xx 10^(-5)...

    Text Solution

    |

  5. K(SP) of M(OH)(x) is 27xx10^(-12) and its solubility in water is 10^(-...

    Text Solution

    |

  6. If the equilibrium constant for the reaction of weak acid HA with stro...

    Text Solution

    |

  7. Calculate the pH of 0.01M solution of AICI(3), (K(a) of [AI(H(2)O)(6)]...

    Text Solution

    |

  8. Calculate the pH of 0.2M sodium butyrate, (K(a) for butyric acid is 2....

    Text Solution

    |

  9. If pK(a) of acetic acid and pK(b) of ammonium hydroxide are 4.76 each....

    Text Solution

    |

  10. A solution with pH2.699 is diluted two time3s, then calculate the pH o...

    Text Solution

    |

  11. The solubility product of a sparingly soluble metal hydroxide [M(OH)(2...

    Text Solution

    |

  12. Determine degree of dissociation of 0.05M NH(3) at 25^(@)C in a soluti...

    Text Solution

    |

  13. If 2H(2)O((g))hArr2H(2(g))+O(2(g)), K(1)=2.0xx10^(-13) 2CO(2(g))hArr...

    Text Solution

    |

  14. For the given reaction, RNH(2)+H(2)OhArr RNH(3)^(+)+OH^(-). Find the...

    Text Solution

    |

  15. Ionisation constant for acids HA and BH^(+) are 10^(-7) and 10^(-3) re...

    Text Solution

    |

  16. Find the relative strength of two weak acids HA (K(a)=8.0xx10^(-5)) an...

    Text Solution

    |

  17. Find the pH at which an acid indicator having concentration 1.0xx10^(-...

    Text Solution

    |

  18. Amonst the following, the total number of compounds whose aqueous sol...

    Text Solution

    |

  19. Find the total number of diprotic acids among the following: H(3)PO(...

    Text Solution

    |

  20. In 1L saturated solution of AgCI [K(sp) (AgCI) = 1.6 xx 10^(-10)], 0.1...

    Text Solution

    |