Home
Class 11
CHEMISTRY
The ratio of pH of solution (1) containi...

The ratio of `pH` of solution `(1)` containing 1 mole of` CH_(3)COONa` and 1 mole of `HCl` and solution `(II)` containing 1 mole of `CH_(3)COONa` and 1 mole of acetic acid in one litre is `:`

A

`1:2`

B

`2:1`

C

`1:3`

D

`3:1`

Text Solution

Verified by Experts

The correct Answer is:
A

`{:(CH_(3)COONa+,HCIrarr,CH_(3)COOH+,NaCI),(1,1,0,0),(0,0,1,1):}`
`:. [CH_(3)COOH]= (1)/(1)=1`
`:. [H^(+)]=Calpha=Csqrt((K_(a))/(C ))= sqrt(K_(a).C)= sqrt(K_(a))`
or `pH_(1)= -(1)/(2)log K_(a)= (1)/(2)pK_(a)`
`{:(CH_(3)COOH+CH_(3),COONa),(1,1):}`
`:. pH=pK_(a)+log((1)/(1))`
`pH_(2)=pK_(a)`
`:. (pH_(1))/(pH_(2))=(1)/(2)`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise|85 Videos
  • IONIC EQUILIBRIUM

    P BAHADUR|Exercise Exercise6|24 Videos
  • GASEOUS STATE

    P BAHADUR|Exercise Exercise -9|1 Videos
  • MOLE AND EQUIVALENT CONCEPT

    P BAHADUR|Exercise Exercise 9 Advanced numerical problems|61 Videos

Similar Questions

Explore conceptually related problems

The Ph of basic buffer mixtures is given by : Ph=Pk_(a)+ log (["Base"])/(["Salt"]) whereas Ph of acidic buffer mixtures is given by : Ph = pK_(a)+"log"(["Salt"])/(["Acid"]) . Addition of little acid or base although shows no appreciable change in Ph for all practical purposes, but sicne the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. The ratio of pH of solution (I) containing 1 mole to pH of solution (II) containing 1 mole of CH_(3)COONa and 1 mole of acetic in one litre is :

a. Calculate the ratio of pH of a solution continaing 1mol . Of CH_(3)COONa +1 mol of HC1 per litre and of other solution containing 1mol of CH_(3)COONa + 1mol of CH_(3)COOH per litre. b. A 0.1M solution of weak acid HA is 1% dissociated at 298k . what is its K_(a) ? what will be the new degree of dissociation of HA and pH when 0.2M of NaA is added to it.

The pH of a solution containing 0.1mol of CH_(3)COOH, 0.2 mol of CH_(3)COONa ,and 0.05 mol of NaOH in 1L. (pK_(a) of CH_(3)COOH = 4.74) is:

Volume of 2 M HCl required to neutralise the solution containing 1"mole" of NH_(4)Cl and 1 "mole" of NaOH is:

P BAHADUR-IONIC EQUILIBRIUM-Exercise7
  1. During neutralisation of an acid by a base, the end point refers for t...

    Text Solution

    |

  2. During neutralisation of an acid by a base, the end point refers for t...

    Text Solution

    |

  3. During neutralisation of an acid by a base, the end point refers for t...

    Text Solution

    |

  4. During neutralisation of an acid by a base, the end point refers for t...

    Text Solution

    |

  5. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

    Text Solution

    |

  6. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

    Text Solution

    |

  7. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

    Text Solution

    |

  8. The ratio of pH of solution (1) containing 1 mole of CH(3)COONa and 1 ...

    Text Solution

    |

  9. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

    Text Solution

    |

  10. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

    Text Solution

    |

  11. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

    Text Solution

    |

  12. The solubility product of SrF(2) in water is 8xx10^(-10). Calculate it...

    Text Solution

    |

  13. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

    Text Solution

    |

  14. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

    Text Solution

    |

  15. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

    Text Solution

    |

  16. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

    Text Solution

    |

  17. A solubility contains one mole each of HA and HB (both are weak acids)...

    Text Solution

    |

  18. A solubility contains one mole each of HA and HB (both are weak acids)...

    Text Solution

    |

  19. A solubility contains one mole each of HA and HB (both are weak acids)...

    Text Solution

    |

  20. A solubility contains one mole each of HA and HB (both are weak acids)...

    Text Solution

    |