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The solubility product of SrF(2) in wate...

The solubility product of `SrF_(2)` in water is `8xx10^(-10)`. Calculate its solubility in `0.1M` NaF aqueous solution.

A

`8xx10^(-10)`

B

`2xx10^(-3)`

C

`2.71xx10^(-10)`

D

`8xx10^(-8)`

Text Solution

Verified by Experts

The correct Answer is:
D
`SrF_(2)hArr Sr^(2+)+2F^(-)`
`K_(SP)=8xx10^(-10)= [Sr^(2+)][F^(-)]^(2)`
`= axx(2a+0.1)^(2) (altltlt0.1)`
`:. a=8xx10^(-8)`
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P BAHADUR-IONIC EQUILIBRIUM-Exercise7
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  2. During neutralisation of an acid by a base, the end point refers for t...

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  3. During neutralisation of an acid by a base, the end point refers for t...

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  4. During neutralisation of an acid by a base, the end point refers for t...

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  5. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

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  6. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

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  7. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

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  8. The ratio of pH of solution (1) containing 1 mole of CH(3)COONa and 1 ...

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  9. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

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  10. The pH of basic buffer mixtures is given by : pH=pK(a)+log((["Base"])/...

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  11. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

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  12. The solubility product of SrF(2) in water is 8xx10^(-10). Calculate it...

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  13. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

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  14. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

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  15. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

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  16. The solubility product of a soluble salt A(x)B(y) is given by: K(SP)= ...

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  17. A solubility contains one mole each of HA and HB (both are weak acids)...

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  18. A solubility contains one mole each of HA and HB (both are weak acids)...

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  19. A solubility contains one mole each of HA and HB (both are weak acids)...

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  20. A solubility contains one mole each of HA and HB (both are weak acids)...

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