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Calculate the dissociation constant of N...

Calculate the dissociation constant of `NH_(4)OH` at `25^(@)C`. If `Delta H^(@)` and `Delta S^(@)` for the given changes are as follows:
`NH_(3)+H^(+)hArrNH_(4)^(+),` , `DeltaH^(@)= -52.2kJ mol^(-1),`
`DeltaS^(@)= +1.67JK^(-1)mol^(-1)`
`H_(2)OhArrH^(+)+OH^(-), DeltaH^(@)=56.6kJ mol^(-1),`
`DeltaS^(@)= -78.2JK^(-1)mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
`1.7xx10^(-5);`
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