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If CH(3)COOH(K(a)=10^(-5)) reacts with N...

If `CH_(3)COOH(K_(a)=10^(-5))` reacts with NaOH at 298K, then find out the value of the maximum rate constant of the reverse reaction at 298 K at the end point of the reaction. Given that the rate constant of the forward reaction is `10^(-11)mol^(-1) L sec^(-1)` at 298 K. Also calculate Arrhenius parameter for backward reaction if `DeltaH_(298K)=44kcal` and `E_(a(f))= 94kcal`.

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The correct Answer is:
`10^(-20),2.71xx10^(+16);`
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